The quadratic polynomial having zeroes are $1$ and $- 2$ is

x^{2} - x - 2

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x^{2} - x + 2

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x^{2} + x - 2

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x^{2} + x + 2

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Solution

The correct option is C $x^{2} + x - 2$
$x^{2} - x + 2$
The zeros are 1 and -2
The zeros can be determine by factorization so -
$b (x) = (x - 1) (x + 2)$
$b (x) = x^{2} + x - 2$

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Similar questions

Q. Question 2
A quadratic polynomial, who zeroes are -3 and 4, is
(a)

x^{2} - x + 12

(b)

x^{2} + x + 12

(c)

\frac{x^{2}}{2} - \frac{x}{2} - 6

(d)

2 x^{2} + 2 x - 24

Q. If

α, β

are the zeroes of the quadratic polynomial

x^{2} + x - 2

, then

(\frac{1}{α} - \frac{1}{β})^{2} =

Q. Find the zeroes of the quadratic polynomial

x^{2} + x - 2

, and verify the relationship between the zeroes and coefficients.

Q. The quadratic equation having roots as

p + 2

and

q + 2

is:

Verify that
(i) 1 and 2 are the zeros of the polynomial, $p (x) = x^{2} - 3 x + 2$ .
(ii) 2 and -3 are the zeros of the polynomial, $q (x) = x^{2} + x - 6.$
(iii) 0 and 3 are the zeros of the polynomial, $r (x) = x^{2} - 3 x$ .

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The quadratic polynomial having zeroes are 1 and −2 is

The correct option is C x2+x−2x2−x+2The zeros are 1 and -2The zeros can be determine by factorization so -b(x)=(x−1)(x+2)b(x)=x2+x−2

The quadratic polynomial having zeroes are $1$ and $- 2$ is

The correct option is C $x^{2} + x - 2$
$x^{2} - x + 2$
The zeros are 1 and -2
The zeros can be determine by factorization so -
$b (x) = (x - 1) (x + 2)$
$b (x) = x^{2} + x - 2$