The quadratic polynomial, whose zeros are $2$ and $3$ , is ......

x^{2} - 5 x - 6

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x^{2} + 5 x - 6

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x^{2} - 5 x + 6

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x^{2} + 5 x + 6

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Solution

The correct option is C $x^{2} - 5 x + 6$
$Since, 2 and 3 are zeros of quadratic polynomial$
$Then, required polynomial is p (x) = (x - 2) (x - 3)$
$\Rightarrow p (x) = x^{2} - 3 x - 2 x + 6$
$\Rightarrow p (x) = x^{2} - 5 x + 6$
Option C is correct.

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x^{2} - 5 x + 6 = 0

x^{2} - 5 x + 6

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x^{2} + 5 x + 6 = 0

x^{2} - 5 x + 6 = 0

x^{2} + 5 x - 6 = 0

x^{2} - 5 x - 6 = 0

p (x) = x^{2} - 5 x + 6

q (x) = x^{2} + 5 x + 4

find the zero's of polynomial $P (x) = x^{2} - 5x + 6$

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