Question

The quantity of charge (in Faraday) required to liberate 33.6 litre Cl${}_2$ from molten NaCl:

Answer 1

$2C{l}^{-}\left(l\right)\to C{l}_2\left(g\right)+2e^{-}$
Thus, the liberation of 1 mole (22.4 L) of chlorine corresponds to 2 moles of electrons or 2 faraday of charge.
Hence, the liberation of 33.6 litre (1.5 moles) of chlorine will require charge of 3 faraday.