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Division Algorithm for a Polynomial

The quotient ...

Question

The quotient and remainder when: $6 x^{2} + x - 15$ is divided by $3 x + 5$ are:

Quotient:

2 x - 3

and Remainder

= 0

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Quotient:

2 x + 3

and Remainder

= 0

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Quotient:

2 x - 3

and Remainder

= 2

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Quotient:

2 x + 3

and Remainder

= 10

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Solution

The correct option is A Quotient: $2 x - 3$ and Remainder $= 0$
Division of $6 x^{2} + x - 15$ by $3 x + 5$ is shown by the image
So, we get Quotient $= 2 x - 3$ and Remainder $= 0$
Hence, option A is correct.

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Similar questions

When the polynomial f(x) = 4x³ + 8x² + 8x + 7 is divided by the polynomial g(x) = 2x² - x + 1, the quotient and the remainder are

3 x^{4} + 6 x^{3} - 6 x^{2} + 2 x - 7

x - 3

3 x^{4} + 2 x^{2} - 3

(x + 1)

Write the quotient and remainder when we divide.

$(6 x^{2} - 31 x + 47) b y (2 x - 5)$

3 x^{4} - x^{3} + 2 x^{2} - 2 x - 4

(x + 2)

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