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Question

The r.m.s value of an a.c of 50Hz is 10amp. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be:

A
2×102 sec and 14.14 A
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B
1×102 sec and 7.07 A
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C
5×103 sec and 7.07 A
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D
5×103 sec and 14.14 A
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Solution

The correct option is D 5×103 sec and 14.14 A
Time taken by alternating current to reach maximum from zero is T4.
where T is the time period of the AC function.
T=1f, Frequency (f)=50 Hz.
So time taken to reach maximum=T4=14f=14×50=5×103 sec
IRMS=I02, I0=Peak value of current.
Peak value of current I0=2×IRMS=2×10=14.14 A

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