Question

the radii of press plunger and pump plunger are in ratio 50:4 . if an effort of 20 kgf acts on the pump plunger , calculate the maximum effort which the press plunger can overcome

Answer 1

$$\begin{gathered} \frac{\mathrm{Load}}{\mathrm{Effort}}=\frac{\mathrm{Cross}-\mathrm{sectional}\mathrm{area}\mathrm{of}\mathrm{press}\mathrm{plunger}}{\mathrm{Cross}-\mathrm{sectional}\mathrm{area}\mathrm{of}\mathrm{pump}\mathrm{plunger}} \\ \frac{\mathrm{Load}}{\mathrm{Effort}}={\left(\frac{\mathrm{Radius}\mathrm{of}\mathrm{Cross}-\mathrm{section}\mathrm{of}\mathrm{press}\mathrm{plunger}}{\mathrm{Radius}\mathrm{of}\mathrm{Cross}-\mathrm{section}\mathrm{of}\mathrm{pump}\mathrm{plunger}}\right)}^2 \\ \frac{\mathrm{Load}}{20}={\left(\frac{50}{4}\right)}^2 \\ \mathrm{Load}={\left(\frac{50}{4}\right)}^2\times 20 \\ =3125\mathrm{kgf} \\ \mathrm{Hence},\mathrm{the}\mathrm{maximum}\mathrm{effort}\mathrm{which}\mathrm{the}\mathrm{press}\mathrm{plunger}\mathrm{can}\mathrm{overcome}=3125\mathrm{kgf} \end{gathered}$$