Question

The radii of two circular ends of a frustum shaped bucket are $15$ cm and $8$ cm. If its depth is $63$ cm, find the capacity of the bucket in litres. (Take $\pi =\frac{22}{7}$)

Answer 1

Here, $h=63$ cm, $R=15$ cm, $r=8$ cm
The volume of frustum
$=\frac{1}{3}\pi h(R^2+r^2+Rr)$ Square cm
$=\frac{1}{3}\times \frac{22}{7}\times 63({15}^2+8^2+15(8\left)\right)$
$=\frac{1}{3}\times \frac{22}{7}\times 63(225+64+120)$
$=\frac{1}{3}\times \frac{22}{7}\times 63\times 409=26994$ cubic cm
$=\frac{26994}{1000}$ litre

$=26.994$ litre

Therefore, capacity of the bucket in litres is $26.994$.