The radii of two circular ends of frustum shape bucket are $14$ cm and $7$ cm Height of the bucket is $30$ cm. How many litres of water it can hold? ( $1$ litre = $1000$ cm) ?

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Solution

Let, the radii of two circular ends of frustum shaped bucket is $r_{1} = 14 c m, r_{2} = 7 c m$ and height of the bucket, $h = 30 c m$
We know that,
Volume of a frustum, $V = \frac{π h}{3} (r_{1}^{2} + r_{1} r_{2} + r_{2}^{2}) = \frac{π \times 30}{3} [14^{2} + (14 \times 7) + 7^{2}] = 10 π \times 343 = 10780 {c m}^{3} = \frac{10780}{1000} l i t r e s = 10.78 l i t r e s .$
Hence, the bucket can carry $10.78 l i t r e s$ of water.

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The radii of two circular ends of frustum shape bucket are 14cm and 7 cm Height of the bucket is 30cm. How many litres of water it can hold? (1 litre =1000cm) ?

Let, the radii of two circular ends of frustum shaped bucket is r1=14cm,r2=7cm and height of the bucket, h=30cmWe know that,Volume of a frustum, V=πh3(r21+r1r2+r22)=π×303[142+(14×7)+72]=10π×343=10780cm3=107801000litres=10.78litres.Hence, the bucket can carry 10.78litres of water.

The radii of two circular ends of frustum shape bucket are $14$ cm and $7$ cm Height of the bucket is $30$ cm. How many litres of water it can hold? ( $1$ litre = $1000$ cm) ?