The radii of two of the first four Bohr's orbits of the hydrogen atom are in the ratio 1 : 4. The energy difference between them may be:
A
Either 12.09 eV or 10.2 eV
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B
Either 2.55 eV or 10.2 eV
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C
Either 13.6 eV or 3.4 eV
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D
Either 3.4 eV or 0.85 eV
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Solution
The correct option is B Either 2.55 eV or 10.2 eV Rn1Rn2=n21n22=14,∴n1n2=12,24,36 etc. Among the first four orbits n1 and n2 can be 1 and 2 or 2 and 4. ∴ Energy difference can be: E2→1=10.2eV or E4→2=2.55eV