The radii of two planets are respectively R1 and R2 and their densities are respectively -1 and -2- The ratio of the accelerations due to gravity at their surface is

Acceleration due to gravity g=4/3 πρ GR ∴ g_1 : g_2 = R_1 ρ_1 : R_2 ρ_2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XIII

Physics

Understanding of Field

The radii of ...

Question

The radii of two planets are respectively $R_{1}$ and $R_{2}$ and their densities are respectively $ρ_{1} a n d ρ_{2}$ . The ratio of the accelerations due to gravity at their surface is

$g_{1} : g_{2} = \frac{ρ_{1}}{R_{1}^{2}} : \frac{ρ_{1}}{R_{2}^{2}}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$g_{1} : g_{2} = R_{1} R_{2} : ρ_{1} ρ_{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$g_{1} : g_{2} = R_{1} ρ_{2} : R_{2} ρ_{1}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$g_{1} : g_{2} = R_{1} ρ_{1} : R_{2} ρ_{2}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
$g_{1} : g_{2} = R_{1} ρ_{1} : R_{2} ρ_{2}$

Acceleration due to gravity $g = \frac{4}{3} π ρ G R ∴ g_{1} : g_{2} = R_{1} ρ_{1} : R_{2} ρ_{2}$

Suggest Corrections

Similar questions

The radii of two planets are respectively $R_{1}$ and $R_{2}$ and their densities are respectively $ρ_{1} a n d ρ_{2}$ . The ratio of the accelerations due to gravity at their surface is

Q. The radii of two planets are

R_{1}

and

R_{2}

respectively and their densities are

ρ_{1}

and

ρ_{2}

respectively. The ratio of the accelerations due to gravity

\frac{g_{1}}{g_{2}}

at their surfaces is

Q. The radii of two planets are

R_{1}

and

R_{2}

, respectively, and their densities are,

ρ_{1}

and

ρ_{2}

respectively. What is the ratio of the acceleration due to gravity at their surfaces?

Q. The radii of two planets are respectively

R_{1}

and

R_{2}

and their densities are respectively

ρ_{1}

and

ρ_{2}

. The ratio of the accelerations due to gravity

(g_{1} / g_{2})

at their surfaces is:

Q. Two planets have radii

r_{1}

and

r_{2}

and their densities are

ρ_{1}

and

ρ_{2}

, respectively. The ratio of acceleration due to gravity on them will be.

Join BYJU'S Learning Program

The radii of two planets are respectively R1 and R2 and their densities are respectively ρ1 and ρ2. The ratio of the accelerations due to gravity at their surface is

The correct option is D g1:g2=R1ρ1:R2ρ2 Acceleration due to gravity g=43 πρ GR ∴ g1:g2 = R1 ρ1 : R2ρ2

The radii of two planets are respectively $R_{1}$ and $R_{2}$ and their densities are respectively $ρ_{1} a n d ρ_{2}$ . The ratio of the accelerations due to gravity at their surface is

The correct option is D
$g_{1} : g_{2} = R_{1} ρ_{1} : R_{2} ρ_{2}$

Acceleration due to gravity $g = \frac{4}{3} π ρ G R ∴ g_{1} : g_{2} = R_{1} ρ_{1} : R_{2} ρ_{2}$