The radioactive decay, 83Bi211→ 81Tl207, takes place in 10 L closed container at 0∘C. Half - life of 83Bi211 is 2.15 min. Starting with 1 mole of 83Bi211, the pressure developed in the container after 4.30 min. will be
1.68 atm
83Bi211→ 81Tl207+2He4
Fraction left =(12)n=(12)4.302.15=14
Moles of He produced = moles of Bi decayed
=1−14=0.75
Pressure developed due to He
=22.4×0.7510=1.68 atm