Question

The radius of a circle is 13 cm and the length of one of its chords is 24 cm. Then the distance of the chord from the centre is

• A. True
• B. False
• C. 6 cm
• D. 12 cm

Answer 1

The correct option is B

False

Given OA = 13 cm
AM = $\frac{AB}{2}=\frac{24}{2}$ = 12 cm
[$\because$ Perpendicular from the centre of a circle to a chord bisects the chord]
In $△$OAM, $\angle OMA={90}^o$
Using Pythagoras' theorem,
$O{M}^2=O{A}^2-A{M}^2$
= ${13}^2-{12}^2$
= 25
$\Rightarrow OM=5cm$