The radius of curvature of a concave mirror is 10 cm. If I want to capture the image of the sun, at what distance from the pole of the mirror would an image be formed?

10 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

20 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

At infinity

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
5 cm

Given, Radius of curvature $= 10 c m$
If the object is placed at infinity the image is formed at the focus.

We know the focal length(F) is half the radius of curvature(R).
$F = \frac{R}{2}$
$F = \frac{10}{2}$
$⟹$ $F = 5 c m$

So the image of the sun is at 5 cm from the pole.

Suggest Corrections

Similar questions

An object is placed at the centre of curvature of a concave mirror of radius of curvature $20 c m$ and focal length $10 c m$ . At what distance from the pole will its image be formed?

Q. An object is placed at a large distance in front of a concave mirror of radius of curvature 40 cm. The image will be formed in front of the mirror at a distance:

(a) 20 cm
(b) 30 cm
(c) 40 cm
(d) 50 cm

The radius of curvature of a concave mirror is 10 cm. If I want to capture the image of the sun, at what distance from the pole of the mirror would an image be formed?

The radius of curvature of a concave mirror is $10 c m$ . At what distance from the pole of the mirror would an image of the sun be formed?

The radius of curvature of a concave mirror is 10 cm. At what distance from the pole of the mirror would an image of the sun be formed?

Join BYJU'S Learning Program

The radius of curvature of a concave mirror is 10 cm. If I want to capture the image of the sun, at what distance from the pole of the mirror would an image be formed?

The correct option is B 5 cm Given, Radius of curvature =10 cm If the object is placed at infinity the image is formed at the focus. We know the focal length(F) is half the radius of curvature(R). F=R2 F=102 ⟹ F= 5 cm So the image of the sun is at 5 cm from the pole.