The radius of Ge nuclide is measured to be twice the radius of $_{4} {B e}^{9}$ . The number of nucleon in Ge are

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Solution

The correct option is A 72
Given that $R_{G e} = 2 R_{B e}$
$\Rightarrow R_{o} (A_{G e})^{1 / 3} = 2 R_{o} (A_{B e})^{1 / 3}$
( $R_{o}$ is a constant, A is atomic number)
${(\frac{A_{G e}}{A_{B e}})}^{1 / 3} = 2$
$A_{G e} = 8 A_{B e}$
$= 8 \times 9 = 72$ RGe=2RBeGiven that $R_{G e} = 2 R_{B e}$

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