The radius of shortest orbit in one electron system is $18$ pm. It may be

_{1}^{1} H

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_{1}^{2} H

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H e^{+}

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L i^{+ +}

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Solution

The correct option is D $L i^{+ +}$
We take $n = 1$ since the $n = 1$ will have the smallest radius.
$r_{n} = \frac{n^{2} r_{B}}{Z} \Rightarrow \frac{0.53 A^{\circ}}{Z} = 0.18 A^{\circ} \Rightarrow Z = 3$

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