The radius of the innermost electron orbit of a hydrogen atom is 5-3 - 10-11 m- Calculate the radius of n - 3 orbit of the same atom-

Radius of orbit (r) r=n^2h^2ϵ_0Zπ me^2=0· 529×n^2ZA^0 For Hydrogen , r_n=n^2r_1 For n=3 , #160; r_3=3^2× 5.3 × 10^ 11=47.7 × 10^ 11 m ...

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Standard XII

Chemistry

Quantum Numbers

The radius of...

Question

The radius of the innermost electron orbit of a hydrogen atom is $5.3 \times 10^{- 11}$ m. Calculate the radius of n = 3 orbit of the same atom.

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Solution

Radius of orbit (r)
$r = \frac{n^{2} h^{2} ϵ_{0}}{Z π m e^{2}} = 0 \cdot 529 \times \frac{n^{2}}{Z} A^{0}$

For Hydrogen , $r_{n} = n^{2} r_{1}$
For $n = 3$ ,
$r_{3} = 3^{2} \times 5.3 \times 10^{- 11} = 47.7 \times 10^{- 11} m$

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The radius of the innermost electron orbit of a hydrogen atom is 5.3×10−11 m. Calculate the radius of n = 3 orbit of the same atom.

Radius of orbit (r)r=n2h2ϵ0Zπme2=0⋅529×n2ZA0For Hydrogen , rn=n2r1For n=3 , r3=32×5.3×10−11=47.7×10−11m

The radius of the innermost electron orbit of a hydrogen atom is $5.3 \times 10^{- 11}$ m. Calculate the radius of n = 3 orbit of the same atom.

Radius of orbit (r)
$r = \frac{n^{2} h^{2} ϵ_{0}}{Z π m e^{2}} = 0 \cdot 529 \times \frac{n^{2}}{Z} A^{0}$

For Hydrogen , $r_{n} = n^{2} r_{1}$
For $n = 3$ ,
$r_{3} = 3^{2} \times 5.3 \times 10^{- 11} = 47.7 \times 10^{- 11} m$