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Bohrs Derivations

The radius of...

Question

The radius of the second Bohr orbit for hydrogen atom is:
(Plank’s const. H = 6.6262 x $10^{- 34}$ Js; mass of electron = 9.1091 x $10^{- 31}$ kg; charge of electron e = 1.60210 x $10^{- 19}$ C; permittivity of vaccum $ϵ_{0} = 8.854185 \times 10^{- 12} k g^{- 1} m^{- 3} A^{2})$

1.65Å

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4.76Å

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0.529Å

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212Å

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Solution

The correct option is D 212Å
Radius of nth Bohr orbit in H-atom = 0.53 $n^{2}$ Å

Radius of II Bohr orbit = 0.53 $\times (2)^{2}$

= 2.12 Å

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Similar questions

h = 6.6262 \times 10^{- 34} J s

= 9.1091 \times 10^{- 31} k g

e = 1.60210 \times 10^{- 19} C

ϵ_{ϕ} = 8.854185 \times 10^{- 12} k g^{- 1} m^{- 3} A^{2})

h = 6.6262 \times 10^{- 34}

m = 9.1091 \times 10^{- 31}

e = 1.60210 \times 10^{- 19}

ϵ_{0} = 8.854185 \times 10^{- 12} C^{2} N^{- 1} m^{- 2}

(Planck's constant, h = 6.262 \times 10^{- 34} Js :

Mass of electron = 9.1091 \times 10^{- 31} kg;

Charge of electron, e = 1.60210 \times 10^{- 19} C;

permittivity of vacuum, ε_{0} = 8.854185 \times 10^{- 12} {kg}^{- 1} m^{- 3} A^{2})

9.1 \times 10^{- 31} K g

= 1.6 \times 10^{- 19} C

6.63 \times 10^{- 34} J - s

8.85 \times 10^{- 12} C^{2} / N m^{2}

(| e | = 1.6 \times 10^{- 19} C, m_{e} = 9.1 \times 10^{- 31} k g, h = 6.6 \times 10^{- 34} J s) .

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