The range in which y=–x2+6x–3 is increasing is
x<3
x>3
7<x<8
5<x<6
The explanation for the correct answer.
Solve for the range where the function y=–x2+6x–3 is increasing.
y=–x2+6x–3
Differentiating with respect to x, we get
y'=–2x+6
y is increasing if y'>0
⇒–2x+6>0⇒–2x>-6⇒2x<6⇒x<3
Hence, option (A) is the correct answer.
Find the value of x:6(3x+2)−5(6x−1)=3(x−8)−5(7x−6)+9x