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Question

The Range of f(x)=x1+x2 is

A
[12,12]
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B
[0,1]
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C
[0,12]
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D
[0,)
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Solution

The correct option is A [12,12]
f(x)=x1+x2

f(x)=(1+x2)×12x×x(1+x2)2

=1x2(1+x2)2

=(1+x)(1x)(1+x2)2

f(x)=0

At x=±1
So maxima will be at 1 & minima will be at 1
f(1)=12
f(1)=12
Range of f(x) is [12,12]

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