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Question

The range of function f(x)=|x1|+|x2|+|x+1|+|x+2| where , x(2,2)

A
6,8
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B
2,4
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C
0,4
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D
1,2
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Solution

The correct option is A 6,8
f(x)=|x1|+|x2|+|x+1|+|x+2|
x(2,2)x2(4,0)
x+2(0,4)
f(x)=|x1|+2x+|x+1|+x+2=4+|x1|+|x+1|
x(2,1)f(x)=4+1x1x=42x(6,8)
x(1,1)f(x)=4+x+1+1x=6
x(1,2)f(x)=4+x1+x+1=4+2x(6,8)
f(x)[6,8]

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