CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The range of function f(x)=sin1[x2+12]+cos1[x212], where [.] is the greatest integer function is

A
{π2,π}
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
{0,12}
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
{π}
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
(0.π2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C {π}
f(x)=sin1[x2+12]+cos1[x212]
=sin1[x2+12]+cos1[x2+121]
=sin1[x2+12]+cos1([x2+12]1)
Since, x2+1212
So, [x2+12] is defined only for the two values.
[x2+12]=0f(x)=sin10+cos1(1)=π
[x2+12]=1f(x)=sin11+cos10=π.
So, range of f(x)=π

flag
Suggest Corrections
thumbs-up
6
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon