wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The range of sin1(2x) is

A
(π2,π2]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(0,π2]
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
(0,π)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(0,π]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B (0,π2]
We know that 2x>0sin1(2x) in order to be defined,we should have 2x1.Therefore, 0<2x10<sin1(2x)π2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon