The range of the function f x - x -1- x isA- 0-2 B- -2-0C- -2 -2-D- -2- -2-

The correct option is D f(x) = x+1/x(x ≠ 0) Now | x+1/x |≥ 2⇒ x+1/xϵ ( ∞, 2]∪ [2,∞) ...

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Range

The range of ...

Question

The range of the function $f (x) = x + \frac{1}{x}$ is

(0, 2)

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(-2, 0)

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Solution

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f (x) = 2 | x - 1 | + | x + 2 |

- 1 \leq x \leq 2

The range of the function $f (x) = \frac{x + 2}{| x + 2 |}$ , $x \neq - 2$ is

f (x) = 2 x^{2} - 3 x + 2

x \in [0, 2]

Range of the function $f (x) = | x - 1 | + | x - 2 | + | x + 1 | + | x + 2 |$ where $x ϵ [- 2, 2]$ , is

f (x) = | x - 1 | + | x - 2 | + | x + 1 | + | x + 2 |

x ϵ [- 2, 2]

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