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Byju's Answer
Standard XII
Mathematics
Range of Quadratic Expression
The range of ...
Question
The range of
y
=
x
−
1
2
x
−
7
,
x
≠
7
2
is
A
R
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B
R
−
{
1
}
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C
R
−
{
1
2
}
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D
R
−
{
0
}
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Solution
The correct option is
C
R
−
{
1
2
}
y
=
x
−
1
2
x
−
7
⇒
2
x
y
−
7
y
=
x
−
1
⇒
x
(
2
y
−
1
)
=
7
y
−
1
⇒
x
=
7
y
−
1
2
y
−
1
∴
y
∈
R
−
{
1
2
}
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