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Rate Constant

The rate cons...

Question

The rate constant for forward and backward reaction of hydrolysis of ester are $1.1 \times 10^{- 2}$ and $1.5 \times 10^{- 3}$ per minute respectively. Equilibrium constant for the reaction is?

A

4.33

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B

5.33

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C

6.33

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D

7.33

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Solution

The correct option is D 7.33

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Q. The rate constant for forward reaction and backward reaction of hydrolysis of ester are

1.1 \times 10^{- 2}

1.5 \times 10^{- 3}

per minute respectively. Equilibrium constant for the reaction is :

C H_{3} C O O C_{2} H_{5} + H_{2} O ⇌ C H_{3} C O O H + C_{2} H_{5} O H

Q. The rate constant for forward and backward reaction of hydrolysis of ester are

1.1 \times 10^{- 2}

1.5 \times 10^{- 3}

per minute respectively.

Equilibrium constant for the reaction is :

C H_{3} C O O C_{2} H_{5} + H_{2} O ⇌ C H_{3} C O O H + C_{2} H_{5} O H

The rate constant for the forward and backward reactions of the hydrolysis of ester are

1.1 \times 10^{- 2}

1.5 \times 10^{- 3}

min^-1respectively. The equilibrium constant of the reaction is:

Q. The rate constant for the forward and backward reactions of hydrolysis of ester are

1.1 \times 10^{- 2}

1.5 \times 10^{- 3}

respectively. The equilibrium constant of the following reaction is:

C H_{3} C O O C_{2} H_{5} + H^{+} ⇌ C H_{3} C O O H + C_{2} H_{5} O H

Q. The rate constants for forward and backward reactions of hydrolysis of ethyl acetate are

1.1 \times 10^{- 2} a n d 1.5 \times 10^{- 3} m i n^{- 1}

respectively. The equilibrium constant for the reaction is

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