1
Question
The rate constant for the forward and backward reactions of the hydrolysis of ester are 1.1×10−2 and 1.5×10−3 min-1 respectively. The equilibrium constant of the reaction is:
The rate constant for the forward and backward reactions of the hydrolysis of ester are 1.1×10−2 and 1.5×10−3 min-1 respectively. The equilibrium constant of the reaction is:
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Solution
The correct option is A 7.33
We know that:
Keq=kfkb
Keq=1.1×10−2min−11.5×10−3min−1
⟹Keq=7.33
7.33
We know that:
Keq=kfkb
Keq=1.1×10−2min−11.5×10−3min−1
⟹Keq=7.33
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