CameraIcon

SearchIcon

MyQuestionIcon

3

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Zero Order Reaction

The rate cons...

Question

The rate constant of forward and backward reactions for certain hypothetical reaction are $1.1 \times 10^{- 2} a n d 1.5 \times 10^{- 3}$ , respectively. The equilibrium constant of the reaction is. (write the value to the nearest integer)

Open in App

Solution

As we know,
$k_{e q} = \frac{k_{f}}{k_{b}} = \frac{1.1 \times 10^{- 2}}{1.5 \times 10^{- 3}} = 7.33.$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The rate constant of forward and backward reactions for certain hypothetical reaction are

1.1 \times 10^{- 2}

1.5 \times 10^{- 3}

respectively. The equilibrium constant of the reaction is:

Q. The rate constant of forward and backward reactions for certain hypothetical reaction are

1.1 \times 10^{- 2}

1.5 \times 10^{- 3}

, respectively. The equilibrium constant of the reaction is

733 \times 10^{- x}

x

Q. The rate constant for forward and backward reaction of hydrolysis of ester are

1.1 \times 10^{- 2}

1.5 \times 10^{- 3}

per minute respectively. Equilibrium constant for the reaction is?

Q. The rate constants for forward and backward reactions of hydrolysis of ethyl acetate are

1.1 \times 10^{- 2} a n d 1.5 \times 10^{- 3} m i n^{- 1}

respectively. The equilibrium constant for the reaction is

The rate constant for the forward and backward reactions of the hydrolysis of ester are

1.1 \times 10^{- 2}

1.5 \times 10^{- 3}

min^-1respectively. The equilibrium constant of the reaction is:

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Integrated Rate Equations

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Zero Order Reaction

Standard VII Chemistry

Join BYJU'S Learning Program

CrossIcon