The rate constant of the reaction $A$ $\to$ $B$ is $0.6 \times 10^{- 3}$ molar per second. If the concentration of A is $5$ M, then the concentration of B after $20$ minutes is:

0.36 M

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0.72 M

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1.08 M

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3.60 M

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Solution

The correct option is B 0.72 M
From the unit of rate constant we get order as 0.

For 0 order reaction:

$a_{o} - a = k t =$ concentration of B ------- 1

Since,

Rate of decomposition of A $=$ Rate of formation of B
$[B] = k t = 0.6 \times 10^{- 3} \times 20 \times 60 = 0.72 M$

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