You visited us 1 times! Enjoying our articles? Unlock Full Access!

Rate Constant

The rate law ...

Question

The rate law for the dimerisation of $N O_{2}$ is $\frac{- d [N O_{2}]}{d t} = k [N O_{2}]^{2}$ .
Which of the following changes will change the value of the specific rate constant (k)?

Doubling the total pressure on the system

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Doubling the temperature

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Both A and B

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B Doubling the temperature
The value of the specific reaction rate (or rate constant) depends on temperature but it is independent of the concentration of reactants or products or total pressure. Thus, doubling the temperature will change the value of the specific reaction rate.

Suggest Corrections

Similar questions

N O_{2} + C O \to C O_{2} + N O

- \frac{d c}{d t} = k [N O_{2}]^{2}

2 {N O}_{2} ⟶ N_{2} O_{2} + O_{2}

- \frac{d [{N O}_{2}]}{d t} = k {[{N O}_{2}]}^{n}

k = 3 \times 10^{- 3} {m o l}^{- 1} L {s e c}^{- 1}

1.5 \times 10^{- 4} m o l L^{- 1} {s e c}^{- 1}

{N O}_{2}

L^{- 1}

For the reaction, 2N₂O₅ → 4NO₂ + O₂, which of the relationship is correct?

2 N O_{2} C l \to 2 N O_{2} + C l_{2}

= k [N O_{2} C l]

N O_{2} C l_{1} N O_{2} + C l

N O_{2} C l + C l_{2} N O_{2} + C l_{2}

N O_{2}

i)

N O_{2}

N_{2} O_{4}

N O_{2}

N_{2} O_{4}

Join BYJU'S Learning Program