The rate law for the reaction $R C l + N a O H (a q) \to R O H + N a C l$ is given by $R a t e = k [R C l]$ . The rate of the reaction will be:

Doubled on doubling the concentration of sodium hydroxide.

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Halved on reducing the concentration of alkyl halide to one half.

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Decreased on increasing the temperature of the reaction.

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Unaffected by increasing the temperature of the reaction.

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Solution

The correct option is B Halved on reducing the concentration of alkyl halide to one half.
As the reaction is first order with respect to RCl, its rate will be halved on reducing the concentration of alkyl halide to one half.

Rate is also affected by temperature, with an increase in temperature rate also increases.

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Similar questions

The rate law for the reaction:
$R C l + N a O H \to R O H + N a C l$ is given by;
Rate = $k [R C l]$ . The rate of this reaction is

(IIT-JEE, 1990)

R C l + N a O H (a q) \to R O H + N a C l

\to

=

R C l + N a O H (a q .) ⟶ R O H + N a C l

= k [R C l]

R C l + N a O H (a q .) \to R O H + N a C l

R a t e = k_{1} [R C l] .

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