Question

The rate law for the reaction

RCl + NaOH $\to$ ROH + NaCl is given by
r $=$ k[RCl] the rate of reaction is

i) double by doubling the conc. of NaOH
ii) is halved by reducing conc. of RCl by one half
iii) is increased by increasing the temperature of reaction
iv) is unaffected by change in temperature
The correct combination is:

• A. i, ii, iv
• B. All are correct
• C. ii, iii
• D. ii, iii, iv

Answer 1

The correct option is C ii, iii

$r\alpha \left[RCI\right]$
$r\alpha K\alpha e^{-Ea/RT}$
$r\uparrow$ as $T\uparrow$

Thus rate of reaction increases as the temperature increses.
So (ii) (iii) are correct option