The rate law for the reaction : $R C l + N a O H (a q) \to R O H + N a C l$ is given by $R a t e = k [R C l]$

Doubled on doubling the concentration of sodium hydroxide

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Halved on reducing the concentration of alkyl halide to one half

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Decreased on increasing the temperature of reaction

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Unaffected by increasing the temperature of the reaction

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Solution

The correct option is B Halved on reducing the concentration of alkyl halide to one half
$R a t e = K [R C l]$
$R a t e$ $α [R C l]$
So on change [RCl] Rate changes accordingly.

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Similar questions

The rate law for the reaction:
$R C l + N a O H \to R O H + N a C l$ is given by;
Rate = $k [R C l]$ . The rate of this reaction is

(IIT-JEE, 1990)

\to

=

R C l + N a O H (a q) \to R O H + N a C l

The rate law for the reaction:
$R C l + N a O H \to R O H + N a C l$ is given by;
Rate = $k [R C l]$ . The rate of this reaction is

(IIT-JEE, 1990)

R C l + N a O H (a q .) ⟶ R O H + N a C l

= k [R C l]

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