Question

The rate law of the reaction A + 2B $\to$ product is given by $\frac{d\left[P\right]}{dt}$ = $K\left[A{]}^2\right[B]$. If A is taken in large excess, the order of the reaction will be:

• A. zero
• B. 1
• C. 2
• D. 3

Answer 1

Answer: (B)

1

If is taken in excess constant, concentration of $A$ doesn't charge much as concentration of $B$ changes & hence we can assume that by changing $B,A$ remain almost same.

Therefore, the rate of the reaction will be simply assumed to be of order $1$ w.r.t. $B$.