The rate of decarboxylation in soda lime process for the following will be:
(a) $H C = C - C O O H$
(b) $C H_{2} = C H - C O O H$
(c) $C H_{3} - C H_{2} - C O O H$

c > b > a

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b > c > a

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a > b > c

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a = b = c

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Solution

The correct option is C $a > b > c$
As unsaturation of molecules increases, decarboxylation become easier so order is $a > b > c$ .

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Similar questions

(A) C H_{3} - C H_{2} - C | C O O H H - - C H - C H_{3}

(B) C H_{3} - C | C O O H H - C H_{2} - - C H - C H_{3}

(C) C | C O O H H_{2} - C H_{2} - C H_{2} - - C H - C H_{3}

C_{10} H_{10} (A)

(B)

H O O C (B) - C H_{2} - C | C H_{2} - C O O H H - C H_{2} - C O O H

C H_{3} - C | C H_{3} H - C H_{2} - C H_{2} - O H

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C H_{3} C H_{3} | C H - O H | C H - C H_{3}

A, B, C

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