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Question

The rate of decomposition of aldehyde (CH3CHO) into CH4 and CO in presence of I2 at 800 K follows the rate law: r=K[CH3CHO][I2]. The decomposition is believed to go to the two step mechanism:

CH3CHO+I2CH3I+HI+CO
CH3I+HICH4+I2
What is the catalyst for the reaction? Which of the two steps is the slower one?

A
HI,Ist step
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B
I2,Ist step
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C
HI,IIst step
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D
I2,IIst step
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Solution

The correct option is D I2,Ist step
Iodine is consumed in the first step and formed in the second step. Hence, iodine is the catalyst. The rate law expression contains the concentrations of acetaldehyde and iodine which appear in the first step. Hence, the first step is the slower step. It is the rate determining step.

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