Question

The rate of diffusion of methane at a given temperature is twice that of a gas x. The molar mass $\left(ingmo{l}^{-1}\right)$ of x is:

• A. 64
• B. 32
• C. 4
• D. 8

Answer 1

The correct option is A 64

$\frac{R_{C{H}_4}}{R_{gas}}=\sqrt{\frac{M_{gas}}{M_{C{H}_4}}}$
$2=\sqrt{\frac{M}{16}}\Rightarrow M=64gmo{l}^{-1}$