Question

The rate of diffusion of methane at a given temperature is twice that of a gas $X$. The molar mass $\left(ingmo{l}^{-1}\right)$ of $X$ is:

• A. 64
• B. 32
• C. 4
• D. 8

Answer 1

The correct option is A 64

As we know,
Use ${\gamma }_{C{H}_4}/{\gamma }_g=\sqrt{\frac{M_g}{M_{C{H}_4}}}$
or $2=\sqrt{\frac{M_g}{16}}$
$\therefore M_g=64gmo{l}^{-1}$