Question

The rate of diffusion of methane at a given temperature is twice that of gas $X$. The molecule weight of $X$ is:

• A. 64
• B. 32
• C. 4
• D. 8

Answer 1

Answer: (A)

64

As we know,

$r$ $\alpha$ $\frac{1}{\sqrt{m}}$

$r_{C{H}_4}$ = 2 $r_x$

$\frac{r_{C{H}_4}}{r_x}=\sqrt{\frac{M_x}{M_{C{H}_4}}}$

$2^2=\frac{M_x}{16}$

$M_x=64$

Hence, the correct option is $\text{A}$