wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The rate of diffusion of methane at at given temprature is twice that of gas X. The molecule weight of X is:


A
64
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
32
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 64
Let, the rate of diffusion of Methane is r1

rate of diffusion of second gas X is r2

We know the rate of diffusion is inversely proportional to molecular weight.

r1r2=M2M1

r12r1=16M2

14=16M2

M2=64

Hence, the correct option is A

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Ideal Gas Model
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon