Question

The rate of diffusion of methane is twice that of the following gas under the same conditions?

• A. $O_3$
• B. $O_2$
• C. $S{O}_2$
• D. $S{O}_3$

Answer 1

The correct option is C $S{O}_2$

Rate of diffusion $\propto \frac{1}{\sqrt{Molecularweight}}$

$\therefore \sqrt{\frac{\left(M\right)methane}{M^1}}=\frac{1}{2}$

$M^1=4$ (Molecular weight of methane)

$\Rightarrow 4\times 16=24$

This corresponds to $S{O}_2$ .