You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Chemistry

Surface Tension

The rate of f...

Question

The rate of flow of water in a capillary tube of length $l$ and radius $r$ is $V$ . The rate of flow in another capillary tube of length $2 l$ and radius $2 r$ for same pressure difference would be

16 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $8 V$
Rate of flow of water through a capillary tube is
V=πPr48ηl
where
P= pressure difference at the two ends of tube
l= length of tube, r= radius of tube
η= coefficient of viscosity of water
As P,η remain the same.
∴V′V=(2r)4(r)4×l2l=162=8
or V′=8V

Suggest Corrections

Similar questions

Q. A capillary tube of length

L

and radius

r

is connected with another capillary tube of the same length but half the radius in series. The rate of steady volume flow of water through first capillary tube under a pressure difference of

p

V

. The rate of steady volume flow through the combination will be (the pressure difference across the combination is

p

)

The rate of steady volume flow of water through a capillary tube of length 'l' and radius 'r' under a pressure difference of P is V. This tube is connected with another tube of the same length but half the radius in series. Then the rate of steady volume flow through them is (The pressure difference across the combination is P)

Q. Water is flowing through a capillary tube at the rate of

20 \times 10^{- 6} m^{3} / s

. Another tube of same radius and double the length is connected in series to the first tube. Now the rate of flow of water in

m^{3} s^{- 1}

is:

Water is flowing through a capillary tube at the rate of $20 \times 10^{- 6} m^{3} / s .$ . Another tube of the same radius and double the length is connected in series to the first tube. Now the rate of flow of water in $m^{3} / s$ is

Q. Two capillary of length

L

and

2 L

and of radius

R

and

2 R

are connected in series. The net rate of flow of fluid through them will be(given rate to the flow through single capillary,

X = \frac{π P R^{4}}{8 η L}

)

Join BYJU'S Learning Program

The rate of flow of water in a capillary tube of length l and radius r is V. The rate of flow in another capillary tube of length 2l and radius 2r for same pressure difference would be

The rate of flow of water in a capillary tube of length $l$ and radius $r$ is $V$ . The rate of flow in another capillary tube of length $2 l$ and radius $2 r$ for same pressure difference would be