Question

The rate of reaction is doubled for every ${10}^{o}C$ rise in temperature. The increase in rate as result of increase in temperature from ${10}^{o}C$ to ${100}^{o}C$ is:

• A. 112
• B. 512
• C. 400
• D. 256

Answer 1

The correct option is B 512

$\frac{k_{t+10}}{k_t}=2$
Now,

${10}^{o}C\to {100}^{o}C$ there is 9 times ${10}^{o}C$ rise.

$r_n=(2{)}^9\times r_1=512\times$ original rate of the reaction.