The ratio between the radii of nuclei with mass numbers $27$ and $125$ is :

5 : 3

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3 : 5

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27 : 125

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125 : 27

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1 : 1

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Solution

The correct option is D $3 : 5$
Radius of nuclei $R = R_{0} A^{1 / 3}$
$∴ \frac{R_{1}}{R_{2}} = {(\frac{A_{1}}{A_{2}})}^{1 / 3}$
or $\frac{R_{1}}{R_{2}} = {(\frac{27}{125})}^{1 / 3} = \frac{3}{5}$

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Similar questions

_{13} A l^{27}

_{52} T e^{125}

_{13}^{27}

_{52}^{125}

x

{(\sqrt{\frac{3}{5}})}^{- x + 1} = \frac{125}{27}

(\frac{125}{27}) \times (\frac{125}{27})^{x} = (\frac{5}{3})^{18}

_{13} A l^{27}

_{52} T e^{125}

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