The ratio in which the plane r- i -2 j -2 k -17 divides the line joining the points -2 i -4 j -7 k and 3 i -5 j -8 k is

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Excentre

The ratio in ...

Question

The ratio in which the plane $r . (ˆ i - 2 ˆ j + 2 ˆ k) = 17$ divides the line joining the points $- 2 ˆ i + 4 ˆ j + 7 ˆ k$ and $3 ˆ i - 5 ˆ j + 8 ˆ k$ is

3 : 7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7 : 10

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 : 10

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 : 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

\vec{r} = 3 \hat{i} + 8 \hat{j} + 3 \hat{k} + λ (3 \hat{i} - \hat{j} + \hat{k}) and \vec{r} = - 3 \hat{i} - 7 \hat{j} + 6 \hat{k} + μ (- 3 \hat{i} + 2 \hat{j} + 4 \hat{k})

\vec{r} = (3 \hat{i} + 5 \hat{j} + 7 \hat{k}) + λ (\hat{i} - 2 \hat{j} + 7 \hat{k}) and \vec{r} = - \hat{i} - \hat{j} - \hat{k} + μ (7 \hat{i} - 6 \hat{j} + \hat{k})

\vec{r} = (\hat{i} + 2 \hat{j} + 3 \hat{k}) + λ (2 \hat{i} + 3 \hat{j} + 4 \hat{k}) and \vec{r} = (2 \hat{i} + 4 \hat{j} + 5 \hat{k}) + μ (3 \hat{i} + 4 \hat{j} + 5 \hat{k})

\vec{r} = (1 - t) \hat{i} + (t - 2) \hat{j} + (3 - t) \hat{k} and \vec{r} = (s + 1) \hat{i} + (2 s - 1) \hat{j} - (2 s + 1) \hat{k}

\vec{r} = (λ - 1) \hat{i} + (λ + 1) \hat{j} - (1 + λ) \hat{k} and \vec{r} = (1 - μ) \hat{i} + (2 μ - 1) \hat{j} + (μ + 2) \hat{k}

\vec{r} = (2 \hat{i} - \hat{j} - \hat{k}) + λ (2 \hat{i} - 5 \hat{j} + 2 \hat{k}) and, \vec{r} = (\hat{i} + 2 \hat{j} + \hat{k}) + μ (\hat{i} - \hat{j} + \hat{k})

\vec{r} = (\hat{i} + \hat{j}) + λ (2 \hat{i} - \hat{j} + \hat{k}) and, \vec{r} = 2 \hat{i} + \hat{j} - \hat{k} + μ (3 \hat{i} - 5 \hat{j} + 2 \hat{k})

\vec{r} = (8 + 3 λ) \hat{i} - (9 + 16 λ) \hat{j} + (10 + 7 λ) \hat{k}

\vec{r} = 15 \hat{i} + 29 \hat{j} + 5 \hat{k} + μ (3 \hat{i} + 8 \hat{j} - 5 \hat{k})

x - 2 y + 3 z = 17

(- 2, 4, 7)

(- 1, - 5, - 10)

¯ ¯ ¯ r = 2 ¯ i - ¯ j + 2 ¯ ¯ ¯ k + ¯ ¯ ¯ λ (3 ¯ i + 4 ¯ j + 2 ¯ ¯ ¯ k)

¯ ¯ ¯ r . (¯ i - ¯ j + ¯ ¯ ¯ k) = 5

\to r . (\to i - 2 \to j + 3 \to k) = 17

- 2 \to i + 4 \to j + 7 \to k

3 \to i + 5 \to j + 8 \to k

x y -

(1, 0, - 3)

(1, - 5, 7)

Join BYJU'S Learning Program