The ratio of area of the triangles ABD and ADC, where AD is the height is:
Given: BD = 2 cm, CD = 3 cm.
Area of a triangle =12×h×b
Ratio of areas of the triangles =△ABD△ADC =12×AD×BD12×AD×CD =BDCD
=23
A point D is taken on the side of BC of ∆ABC such that BD = 2DC. Then