Question

The ratio of charge densities on the surface of two conducting spheres is 3 : 2. lithe radii of t: the spheres are 4 cm and 8 cm the ratio of the electric potential on the surfaces of the sphere 2 is

• A. 3 : 4
• B. 3 : 1
• C. 1 : 3
• D. 4 : 9

Answer 1

The correct option is C 1 : 3

Ratio of charge densities $=3:2$ spheres are $4cm$ and $8cm$

spheres ratio $=4:8=1:2$

$E_1:E_2=?$

$E$ $\alpha$ $\frac{\lambda }{r}$

$\frac{E_1}{E_2}=\frac{{\lambda }_1}{{\lambda }_2}\times \frac{r_2}{r_1}$

$=\frac{3}{2}\times \frac{2}{1}$

$=3:1$

$E_2:E_1=1:3$