The ratio of densities of two substances a and b is 3 : 1 and the relative density of object b is 4. The density of substance a is

12 \times 10^{3} k g m^{- 3}

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1.1 g c m^{- 3}

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120 g c m^{- 3}

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0.75 g c m^{- 3}

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Solution

The correct option is B $12 \times 10^{3} k g m^{- 3}$
$\frac{d_{a}}{d_{b}} = \frac{3}{1}$
$R D_{b} = 4 = \frac{d_{b}}{d_{w}}$
$\frac{d_{a}}{d_{w}} = 3 \frac{d_{b}}{d_{w}} = 3 \times 4 = 12$
$d_{a} = 12 \times \frac{1 g}{c m^{3}}$
$= 12 g c m^{- 3}$
or $12 \times 10^{3} k g m^{- 3}$

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The ratio of densities of two substances a and b is 3 : 1 and the relative density of object b is 4. The density of substance a is

The correct option is B 12×103kgm−3dadb=31RDb=4=dbdwdadw=3dbdw=3×4=12da=12×1gcm3=12gcm−3or 12×103kgm−3

The correct option is B $12 \times 10^{3} k g m^{- 3}$
$\frac{d_{a}}{d_{b}} = \frac{3}{1}$
$R D_{b} = 4 = \frac{d_{b}}{d_{w}}$
$\frac{d_{a}}{d_{w}} = 3 \frac{d_{b}}{d_{w}} = 3 \times 4 = 12$
$d_{a} = 12 \times \frac{1 g}{c m^{3}}$
$= 12 g c m^{- 3}$
or $12 \times 10^{3} k g m^{- 3}$