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Equivalent, Molar Conductivity and Cell Constant

The ratio of ...

Question

The ratio of $\frac{Λ_{m}}{Λ_{e q}}$ for $C a_{3} (P O_{4})_{2}$ is:

A

6

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B

4

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C

3

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D

2

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Solution

The correct option is A 6
The ratio of $\frac{Λ_{m}}{Λ_{e q}}$ for $C a_{3} (P O_{4})_{2}$ is 6.
The relationship between the molar conductivity and the equivalent conductivity is as given below.
$Λ_{m} = Λ_{e q} \times$ valence factor.
For $C a_{3} (P O_{4})_{2}$ , the valency factor is $2 \times 3 = 6$ .

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