The ratio of K p - K c for the reaction- CO g -1-2 O 2 g - CO 2 g -A- 1 B- RT -1 - 2C- RT D- RT 1 - 2

The correct option is B (RT)^ 1/2 nbsp;We know that K_p = K_c(RT)^ n CO(g) + 12(O_2)(g) → CO_2(g) n = n_p n_r n = 1 (1 + 12) = 12 So, K_pK_c = (RT)^ 1/ ...

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Standard XII

Chemistry

Derivation of Kp and Kc

The ratio of ...

Question

The ratio of $K_{p} / K_{c}$ for the reaction, $C O (g) + \frac{1}{2} O_{2} (g) ⇌ C O_{2} (g)$ is

1

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R T

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(R T)^{1 / 2}

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(R T)^{- 1 / 2}

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Solution

The correct option is D $(R T)^{- 1 / 2}$
We know that
$K_{p} = K_{c} (R T)^{△ n}$
$C O (g) + \frac{1}{2} (O_{2}) (g) \to C O_{2} (g)$
$△ n = n_{p} - n_{r}$
$△ n = 1 - (1 + \frac{1}{2}) = - \frac{1}{2}$
So, $\frac{K_{p}}{K_{c}} = (R T)^{- 1 / 2}$

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Derivation of Kp and Kc

Standard XII Chemistry

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The ratio of Kp/Kc for the reaction, CO(g)+12O2(g)⇌CO2(g) is

The correct option is D (RT)−1/2 We know that Kp=Kc(RT)△n CO(g)+12(O2)(g)→CO2(g) △n=np−nr △n=1−(1+12)=−12 So, KpKc=(RT)−1/2

The ratio of $K_{p} / K_{c}$ for the reaction, $C O (g) + \frac{1}{2} O_{2} (g) ⇌ C O_{2} (g)$ is

The correct option is D $(R T)^{- 1 / 2}$
We know that
$K_{p} = K_{c} (R T)^{△ n}$
$C O (g) + \frac{1}{2} (O_{2}) (g) \to C O_{2} (g)$
$△ n = n_{p} - n_{r}$
$△ n = 1 - (1 + \frac{1}{2}) = - \frac{1}{2}$
So, $\frac{K_{p}}{K_{c}} = (R T)^{- 1 / 2}$