Question

The ratio of Kinetic energy to the total energy of an electron in Bohr orbit is

• A. 1:1
• B. 1:3
• C. 1:2
• D. 2:1

Answer 1

The correct option is A

1:1

$K_E=\frac{Z{e}^2}{8\pi {\epsilon }_{0}r}u=\frac{-Z{e}^2}{8\pi {\epsilon }_{0}r}TE=\frac{-Z{e}^2}{8\pi {\epsilon }_{0}r}$